Part D In talking about interference, particularly with light, you will most likely speak in terms of phase differences, as well as waveleng

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Part D In talking about interference, particularly with light, you will most likely speak in terms of phase differences, as well as wavelength differences. In the mathematical description of a sine wave, the phase corresponds to the argument of the sine function. For example, in the function y=Asin(kx)y=Asin⁡(kx), the value of kxkx at a particular point is the phase of the wave at that point. Recall that in radians a full cycle (or a full circle) corresponds to 2π2π2 pi radians. How many radians would the shift of half a wavelength from the previous part correspond to? Express your answer in terms of ππpi.

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Nho 2 months 2021-07-15T08:05:21+00:00 1 Answers 5 views 0

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    2021-07-15T08:06:31+00:00

    Answer:

    θ = π / 2

    Explanation:

    In the interference phenomenon the process is described by the equations

           d sin θ = m λ                for constructive interference and

            d sin θ = (m + 1/2) λ    for destructive interference

    m is an integer that represents the position of the interference m = 0 for this case the first maximum occurs in

          d sin θ = 0

    for m=1

            sin θ = λ/d

    that is, the angle is

            θ = 0

    the first point of destructive interference is

           d sin θ = ½ λ

            sin θ = ½ λ/ d

    for this value to be maximum the angle of the sine function is

            sin θ = +1

            θ = π / 2

    this is the angle to have destructive interference, this is that there is no line at the point

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