Part B: Quantitative Problems when Vf = 0 4. A 7 kg. bowling ball traveling down a test track at 8 m/s hits a pile

Question

Part B: Quantitative

Problems when Vf = 0

4. A 7 kg. bowling ball traveling down a test track at 8 m/s hits a pile of
dirt, and comes to a halt after 0.01 seconds.

a. Find Av and mav.

b. With what impact force did the bowling ball hit the pile of dirt?

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Thiên Di 4 years 2021-08-05T02:56:30+00:00 1 Answers 8 views 0

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  1. thuhuong
    0
    2021-08-05T02:58:13+00:00
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    Answer:

    (a)

    \triangle v=-8\ m/s\\\triangle mv=-56\ kg.m/s

    (b)

    5600 N

    Explanation:

    Change in velocity, \triangle v is expressed as

    \triangle v= v_f -v_i

    Where v represent the velocity and subscripts f and i represent final and initial respectively. Given that the ball finally comes to rest, its final velocity is taken as 0. Substituting 0 for final velocity and the given figure of 8 m/s for initial velocity then the change in velocity is given by

    \triangle v=0-8=-8\ m/s

    To find the change in momentum, m\triangle v then we substitute 7 kg for m and -8 m/s for \triangle v therefore \triangle\ v=7 Kg\times -8 m/s=-56\ Kg.m/s

    (b)

    The impact force, F is equivalent to ma where m is the mass of the ball and a is the acceleration. Here, acceleration is given by dividing the change in velocity by time ie

    a=\frac {\triangle v}{t}=\frac { v_f -v_i}{t}

    Substituting t with 0.05 s then a=\frac {\triangle v}{t}=\frac { v_f -v_i}{t}=\frac {-8}{0.01}=-800 m/s^{2}

    Since F=ma then substituting m with 7 Kg we get that F=7*-800=-5600 N

    Therefore, the impact force is equivalent to 5600 N

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