Organ pipe A, with both ends open, has a fundamental frequency of 475 Hz. The third harmonic of organ pipe B, with one end open, has the sam

Question

Organ pipe A, with both ends open, has a fundamental frequency of 475 Hz. The third harmonic of organ pipe B, with one end open, has the same frequency as the second harmonic of pipe A. Use 343 m/s for the speed of sound in air. How long are (a) pipe A and (b) pipe B?

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Vodka 1 year 2021-09-01T20:49:12+00:00 1 Answers 9 views 0

Answers ( )

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    2021-09-01T20:50:35+00:00

    Answer:

    The length of organ pipe A is [tex]L = 0.3611 \ m[/tex]

    The length of organ pipe B is  [tex]L_b = 0.2708 \ m[/tex]

    Explanation:

    From the question we are told that

        The fundamental frequency is  [tex]f = 475 Hz[/tex]

         The speed of sound is  [tex]v_s = 343 \ m/s[/tex]

    The fundamental frequency of the organ pipe A  is mathematically represented as

            [tex]f= \frac{v_s}{2 L}[/tex]

    Where L is the length of  organ pipe

       Now  making L the subject

            [tex]L = \frac{v_s}{2f}[/tex]

    substituting values

            [tex]L = \frac{343}{2 *475}[/tex]

            [tex]L = 0.3611 \ m[/tex]

    The second harmonic frequency of the  organ pipe A is mathematically represented as

           [tex]f_2 = \frac{v_2}{L}[/tex]

    The third harmonic frequency of the  organ pipe B is mathematically represented as      

          [tex]f_3 = \frac{3 v_s}{4 L_b }[/tex]

    So from the question

           [tex]f_2 = f_3[/tex]

    So

        [tex]\frac{v_2}{L} = \frac{3 v_s}{4 L_b }[/tex]

    Making  [tex]L_b[/tex] the subject

         [tex]L_b = \frac{3}{4} L[/tex]

    substituting values

        [tex]L_b = \frac{3}{4} (0.3611)[/tex]

        [tex]L_b = 0.2708 \ m[/tex]

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