One way to probe the nucleus is to bombard a sample with high-energy electrons. To learn about the nuclear structures in a sample, the de Br

Question

One way to probe the nucleus is to bombard a sample with high-energy electrons. To learn about the nuclear structures in a sample, the de Broglie wavelengths of these electrons would need to be a little smaller than a nuclear radius. Estimate the energy of such electrons. Give your answer in electron-volts. (Assume that the wavelength used is about 9.0 fm.) eV

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Mộc Miên 3 years 2021-08-22T01:53:41+00:00 1 Answers 6 views 0

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    2021-08-22T01:54:48+00:00
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    Answer:

    E = 1.38 x 10⁸ eV = 138 MeV

    Explanation:

    The energy associated with the given wavelength can be found from the following formula:

    E = \frac{hc}{\lambda}

    where,

    E = Energy of electron = ?

    h = Plank’s Constant = 6.625 x 10⁻³⁴ J.s

    c = Speed of Light = 3 x 10⁸ m/s

    λ = wavelength = 9 fm = 9 x 10⁻¹⁵ m

    Therefore,

    E = \frac{(6.625\ x\ 10^{-34}\ J.s)(3\ x\ 10^8\ m/s)}{9\ x\ 10^{-15}\ m}\\\\E = (2.21\ x\ 10^{-11}\ J)(\frac{1\ eV}{1.6\ x\ 10^{-19}\ J})

    E = 1.38 x 10⁸ eV = 138 MeV

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