On January 22, 1943, in Spearfish, South Dakota, the temperature rose from −4.00°F to 45.0°F over the course of two minutes (the current wor

Question

On January 22, 1943, in Spearfish, South Dakota, the temperature rose from −4.00°F to 45.0°F over the course of two minutes (the current world record for the fastest recorded temperature change). By how much did the temperature change on the Celsius scale?

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Doris 5 months 2021-08-13T01:52:51+00:00 1 Answers 34 views 0

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    2021-08-13T01:54:06+00:00

    Answer:

    The change on the Celsius scale is 27.22 °C.

    Explanation:

    The conversion of Fahrenheit to Celsius is the following:

    T = \frac{5}{9}(^{\circ} F - 32)

    So, we need to convert T₁ and T₂ from °F to °C:

    T_{1} = \frac{5}{9}(^{\circ} F - 32) = \frac{5}{9}(- 4 - 32) = -20 ^{\circ} C

    T_{2} = \frac{5}{9}(^{\circ} F - 32) = \frac{5}{9}(45 - 32) = 7.22 ^{\circ} C

    Hence, the change on the Celsius scale is:

     \Delta T = T_{2} - T_{1} = 7.22 - (-20) = 27.22 ^{\circ} C

    Therefore, the change on the Celsius scale is 27.22 °C.

    I hope it helps you!

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