“On earth, you have a pendulum of length L that oscillates with period T. Your friend lives on a planet where the acceleration of gravity is

Question

“On earth, you have a pendulum of length L that oscillates with period T. Your friend lives on a planet where the acceleration of gravity is four times as big as it is on the earth. What should be the length of a pendulum on your friend s planet so that it also oscillates with the same period T

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Tài Đức 6 months 2021-08-22T05:32:30+00:00 2 Answers 1 views 0

Answers ( )

    0
    2021-08-22T05:33:53+00:00

    Answer:

    4L

    Explanation:

    Data provided in the question according to the question is as follows

    Length = L

    Gravity = G

    For friend

    Length = ?

    Growth = 4G

    Moreover,

    T_1 = T_2

    Based on the above information ,

    Now we have to apply the simple pendulum formula which is shown below:

    T = 2\pi \frac{L}{G}

    Now equates these equations in both sides

    2\pi \frac{L}{G} = 2\pi \frac{L}{4G}

    So after solving this, the length of the pendulum is 4L

    0
    2021-08-22T05:33:56+00:00

    Answer:

    the length of a pendulum on your friend s planet should be 4 times than that on earth

    Explanation:

    We know that time period of simple pendulum is given by

    T= 2\pi\sqrt{\frac{L}{g} }

    L= length of pendulum

    g= acceleration due to gravity

    therefore, Let T_1 and T_2 be the time period of the earth and other planet respectively.

    \frac{T_1}{T_2} =\sqrt(\frac{L_1}{L_2}\times\frac{g_2}{g_1})

    ATQ

    T_1=T_2=T,   g_2=4g_1

    Putting the values in above equation and solving we get

    \frac{L_1}{L_2} =\frac{1}{4}

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