On a rectangle with length 100 m, width 50m and 2 vehicles stationed together. Find the time that they meet given that car A travels 5 m/s a

Question

On a rectangle with length 100 m, width 50m and 2 vehicles stationed together. Find the time that they meet given that car A travels 5 m/s and leaves 3 seconds before car B, and car B is traveling at 3 m/s in the opposite direction. Can you create a generic equation from the previous scenario

in progress 0
Nho 3 years 2021-08-05T23:33:09+00:00 1 Answers 14 views 0

Answers ( )

  1. danthu
    0
    2021-08-05T23:35:03+00:00
    Reply

    Answer:

    T=35.625sec

    Explanation:

    From the question we are told that:

    Length L=100 m

    Width W=50m

    Velocity of Car A V_A=5m/s

    Velocity of Car B V_B=3m/s

    Distance traveled by car A before car B moves

    d_l=5*3

    d_l=15

    Therefore total distance traveled at same time interval

    D=total\ distance-d_l

    Where

    Total distance=Perimeter of rectangle

    P=2(L+B)

    P=2(100+50)

    P=300

    Therefore

    D=total\ distance-d_l

    D=300-15\\D=285m

    Generally the equation for time taken to meet is mathematically given by

    T=\frac{Distance D}{Relative\ speed V_r}

    Where

    Relative speed = Speed of car A +Speed of car B

    V_r=V_A+V_B

    V_r=5+3

    V_r=8m/s

    Therefore the time taken to meet

    T=\frac{ D}{ V_r}

    T=\frac{ 285}{ 8}

    T=35.625sec

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )