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## On a frictionless surface, a 32 kg student pushes a 43 kg student. If the 32 kg student slides back at 2.4 m/s, how fast will the 43 kg stud

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## Answers ( )

Answer:The 43kg student will be sliding at 1.79m/s opposite the direction the 34kg student is going.

Explanation:Conservation of linear momentum!

The law of conservation of momentum says that in an isolated system, the momentum before must equal the momentum after:

.

For our two students

(notice the – sign in -2.4m/s, this means going to the left)since the students were not moving at first, , therefore we have

solving for gives

Hence the 43kg student will be sliding at 1.79m/s to the right.