Of 24 pounds of salt water, 8% is salt. Of another mixture, 4% is salt. How many pounds of the second mixture should be added to the first m

Question

Of 24 pounds of salt water, 8% is salt. Of another mixture, 4% is salt. How many pounds of the second mixture should be added to the first mixture in order to get a mixture of 5% salt. Write an equation to represent the total amount of salt water, in pounds, present. Let x represent the total amount of 4% salt water, let y represent total amount of the end 5% salt solution.

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Edana Edana 4 years 2021-09-05T11:43:10+00:00 1 Answers 31 views 0

Answers ( )

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    2021-09-05T11:44:18+00:00

    Answer:

    (0.08 × 24) + (0.04 * x) = 0.05 * (x + 24)

    Step-by-step explanation:

    Given the following :

    Amount of salt water = 24 pounds ;% of salt = 8% = 0.08

    Of another mixture ; salt = 4% = 0.04

    Total amount of 4% salt water = x

    y = total amount of the end 5% solution

    Amount of salt in first and second mixture = 5% of salt in end solution

    Amount of salt in first mixture = 0.08 × 24

    Amount of salt in second mixture = 0.04 * x

    Amount of salt in end solution = 0.05 * (total amount of mixture) = 0.05 * (x + 24)

    (0.08 × 24) + (0.04 * x) = 0.05 * (x + 24)

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