Nitrogen and hydrogen react to form ammonia, like this:N2(g)+3H2(g)→2NH3(g)Use this chemical equation to answer the questions below.Suppose

Question

Nitrogen and hydrogen react to form ammonia, like this:N2(g)+3H2(g)→2NH3(g)Use this chemical equation to answer the questions below.Suppose 135, mmol of N₂ and 405, mmol of H₂ are added to an empty flask, How much N₂ will be in the flask at equilibrium? a. Noneb. Some, but less than 135, mmol.c. 135,mmold. More than 135, mmol.Suppose 235, mmol of NH₃ are added to an empty flask, How much N₂ will be in the flask at equilibrium? a. Noneb. Some, but less than 118, mmol.c. 118,mmold. More than 118, mmol.

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Thiên Thanh 4 years 2021-07-13T04:47:03+00:00 1 Answers 18 views 0

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  1. thucuc
    0
    2021-07-13T04:48:58+00:00
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    Answer:

    Option A is correct, there will be no N2 left in the flask

    Explanation:

    Step 1 : Data given

    Number of moles of N2 = 135 mmol = 0.135 mol

    Number of moles of H2 = 405 mmol = 0.405 mol

    Step 2: The reaction

    N2(g)+3H2(g)→2NH3(g)

    Step 3:

    For 1 mol N2 we need 3 moles H2 to produce 2 moles NH3

    Both will completely react. There is no limiting reactant.

    There will be produce 0.270 moles NH3.

    Option A is correct, there will be no N2 left in the flask

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