NEED HELP ASAP! When heated, cyclopropane is converted to propene. Rate constants for this reaction at 470. °C and 510. °C are k

Question

NEED HELP ASAP!

When heated, cyclopropane is converted to propene. Rate constants for this reaction at 470. °C and 510. °C are k1 = 1.10 × 10-4 s-1 and k2 = 1.02 × 10-3 s-1, respectively. Determine the activation energy, Ea, from these data.

in progress 0
Vodka 4 years 2021-07-27T08:15:47+00:00 1 Answers 30 views 0

Answers ( )

  1. thuhuong
    0
    2021-07-27T08:17:01+00:00
    Reply

    Answer:

    1.06 × 10^5 J

    Explanation:

    We have to use the formula;

    log(k2/k1) = Ea/2.303 ×R (1/T1 – 1/T2)

    Given that;

    k1 = 1.10 × 10-4 s-1

    k2= 1.02 × 10-3 s-1

    Ea=?

    R=8.314 Jmol-1K-1

    T1= 470. °C

    T2= 510. °C

    Hence;

    log(1.02 × 10-3 s-1/1.10 × 10-4 =Ea/2.303 ×8.314(1/470 -1/510)

    0.9672 = Ea/19.122(2.13 – 1.96) × 10^-3

    0.9672= Ea/19.122(0.17) × 10^-3

    0.9672= 1.7 ×10^-4 Ea/19.122

    19.122 × 0.9672 = 1.74 × 10^-4Ea

    Ea= 19.122 × 0.9672/1.74 × 10^-4

    Ea= 18.495/1.74 × 10^-4

    Ea= 1.06 × 10^5 J

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )