n electric motor rotating a workshop grinding wheel at 1.10 102 rev/min is switched off. Assume the wheel has a constant negative angular ac

Question

n electric motor rotating a workshop grinding wheel at 1.10 102 rev/min is switched off. Assume the wheel has a constant negative angular acceleration of magnitude 1.92 rad/s2. (a) How long does it take the grinding wheel to stop?

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Mít Mít 5 months 2021-08-18T08:36:14+00:00 1 Answers 1 views 0

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    2021-08-18T08:37:51+00:00

    Answer:

    Time taken to stop = 6 sec

    Explanation:

    Given:

    Rotation of wheel = 1.10 × 10² rev/min

    Final velocity (v) = 0

    Angular acceleration (a) = – 1.92 rad/s²

    Find:

    Time taken to stop

    Computation:

    Initial velocity (u) = (1.10 × 10² × 2π rad) / 60 sec

    Initial velocity (u) = 11.52 rad / sec

    We know that,

    V = U +at

    t = (v-u)a

    t = (0 – 11.52) / (-1.92)

    Time taken to stop = 6 sec

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