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Monochromatic (single-wavelength) light falling on two slits 0.016 mm apart produces the fifth-order bright spot at an 8.8◦angle. What is th
Question
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Answers ( )
Given Information:
distance = d = 0.016 mm = 0.0016 cm = 0.000016 m
Angle = θ = 8.8°
bright spot = m = 5
Required Information:
Wavelength = λ = ?
Answer:
Wavelength = 4.89×10⁻⁷ m
Explanation:
Monochromatic light passes through a double slit. The corresponding diffraction is given by the equation:
dsinθ = mλ
where d is the distance between two slits, m is the order of the diffraction, θ is the angle and λ is the wavelength of the light wave.
λ = dsinθ/m
λ = 0.016*sin(8.8°)/5
λ = 4.89×10⁻⁷ m
Therefore, the wavelength of the monochromatic light falling on two slits is 4.89×10⁻⁷ m
Answer:
the wavelength of the light used is 4.8 × 10⁻⁷m
Explanation:
We have given distance between the two slits
Angle
We know that for nth order fringe
In question it is given that 5th order so n =5