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Monochromatic light falls on a screen 1.60 m from two slits separated by 2.11 mm. The first- and second-order bright fringes are separated b
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Answers ( )
Answer:
725 x10^-9m
Explanation:
We know that the optical path difference is (ax)/D
Where
a=2.11mm
D=1.60m
x= position on the screen
the optical path differences varies of lambda = wavelength
That is BTW two bright fringes
So therefore
x2-x1=lambda x D/a
lambda = ( x2 – x1) x a/D = 0.55 x 10^-3 x 2.11E-3 / 1.60 = 725nm