## Mollie is using springs to hang art projects. She hang a 3.0kg picture on one particular spring and it stretches from 30 cm to 45 cm long. W

Question

Mollie is using springs to hang art projects. She hang a 3.0kg picture on one particular spring and it stretches from 30 cm to 45 cm long. What is the spring constant for that spring? If she hangs a 2 kg picture beneath the first one, how long will the spring get?

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1 year 2021-07-26T22:11:40+00:00 1 Answers 11 views 0

1. Spring constant, k = 784 N/m

Distance = 49 cm

Explanation:

Given:

Mass, m₁ = 3 kg

Distance, x₁ = 30 cm

Distance, x₂ = 45 cm

Spring constant, k = ?

(a)

When the mass is being stretched at a height then potential energy gets converted to kinetic energy.

Potential energy = kinetic energy

$$mgh = \frac{1}{2} k(h-x)^2$$

On substituting the value, we get:

$$3 X 9.8 X 0.3 = \frac{1}{2} X k X (0.45 – 0.3)^2\\ \\8.82 = \frac{1}{2} X k X (0.15)^2\\ \\17.64 = k X 0.0225\\\\k = \frac{17.64}{0.0225}\\ \\k = 784 N/m$$

(b)

Total mass, m = 3 kg + 2kg

= 5 kg

Distance, x = ?

We know:

Force = mg

Force on a spring = kx

$$mgh = \frac{1}{2}k (x – h)^2$$

$$5 X 9.8 X 0.3 = \frac{1}{2} X 784 X (x – 0.3)^2\\\\14.7 = 392 (x – 0.3)^2\\\\0.0375 = ( x – 0.3)^2\\\\0.194 = x – 0.3\\\\x = 0.494 m$$

The spring stretches to 0.494m or 49 cm when a weight of 2kg is added