mn giúp em bài l/giác: a) Cos10x – Cos8x – Cos6x + 1= 0 b) (1-Tanx)(1+sin2x) = 1 + Tanx c) (1+2sinx)^2Cosx = 1 + sinx + cosx d) (2sinx -1)(2cosx +

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mn giúp em bài l/giác:
a) Cos10x – Cos8x – Cos6x + 1= 0
b) (1-Tanx)(1+sin2x) = 1 + Tanx
c) (1+2sinx)^2Cosx = 1 + sinx + cosx
d) (2sinx -1)(2cosx + sin x) = Sin2x – Cosx
e) Sin2x – Cos2x = 1 + Căn2(Sin2x + Sin4x)

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Latifah 1 year 2020-11-29T06:31:30+00:00 0 Answers 17 views 0

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