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## Michael jogs at 3 miles per hour and Jack runs at 4.5 miles per hour. If Michael starts at 2:00 pm and Jack starts on the same course at 2:2

Question

Michael jogs at 3 miles per hour and Jack runs at 4.5 miles per hour. If Michael starts at 2:00 pm and Jack starts on the same course at 2:20 pm, at what time and mileage will Jack catch up to Michael?

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Mathematics
7 months
2021-07-19T09:03:44+00:00
2021-07-19T09:03:44+00:00 1 Answers
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## Answers ( )

Answer:It will take Jack 40 minutes to cover the same distance which Micheal covers in 60 minutes. Both will meet at 3 miles distance at 3 pm.

Step-by-step explanation:Micheal runs 3 miles in one hour or 60 minutes.

In one minute he runs 3/60= 1/20 or 0.05miles.

Jack runs 4.5 miles in one hour or 60 minutes.

In one minute he runs 4.5/60= 45/600= 9/120= 3/40 or 0.075 miles.

So Jack is 0.075/0.05 = 1.5 times faster than Micheal.

or Micheal is 1.5 times slower than Jack.

Jack starts from 2:20 pm and at 3 pm he will run 0.075(40 minutes)= 3miles

Micheal start at 2:00 pm and at 3 pm he will run 0.05(60 minutes)= 3 miles

So at 3 pm both will have covered equal distance= 3miles.

It will take Jack 40 minutes to cover the same distance which Micheal covers in 60 minutes. Both will meet at 3 miles distance at 3 pm.