Match the solutions to the descriptions of the freezing points.a. One mole of the ionic compound Na3PO4 dissolved in 1000 g H2O b. One mole

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Match the solutions to the descriptions of the freezing points.a. One mole of the ionic compound Na3PO4 dissolved in 1000 g H2O b. One mole of the ionic compound CuSO4 dissolved in 1000 g H2O c. One mole of the nonelectrolyte C6H12O6 dissolved in 1000 g H2O1. Highest freezing point 2. Intermediate freezing point 3. Lowest freezing point

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Thành Đạt 3 years 2021-08-17T04:53:00+00:00 1 Answers 23 views 0

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  1. ngochoa
    0
    2021-08-17T04:54:50+00:00
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    Explanation:

    Depression in Freezing point

    = Kf × i × m

    where m is molality , i is Van’t Hoff factor, m = molality

    Since molality and Kf remain the same

    depression in freezing point is proportional to i

    i= 2 for CuSO4 ( CuSO4———-> Cu+2 + SO4-2

    i=1 for C2h6O

    i= 3 for MgCl2 ( MgCl2——–> Mg+2+ 2Cl-)

    So the freezing point depression is highest for MgCl2 and lowest for C2H6O

    so freezing point of the solution = freezing point of pure solvent- freezing point depression

    since MgCl2 has got highest freezing point depression it will have loweest freezing point and C2H6O will have highest freezing point

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