Maintaining constant pressure, the volume of a gas is increased from 12,0 L to 32.0 L by heating it. If the original temperature was 2

Question

Maintaining constant pressure, the volume of a gas is increased from 12,0 L
to 32.0 L by heating it. If the original temperature was 23.0°C, what is the
new temperature? *
23. 45 K
61.33 K
789.33 K
567.87 K

in progress 0
Thu Thảo 2 months 2021-07-31T19:21:20+00:00 1 Answers 4 views 0

Answers ( )

    0
    2021-07-31T19:23:19+00:00

    Answer:

    790 K

    Explanation:

    Step 1: Given data

    • Initial volume of the gas (V₁): 12.0 L
    • Initial temperature of the gas (T₁): 23.0 °C
    • Final volume of the gas (V₂): 32.0 L

    Step 2: Convert 23.0 °C to Kelvin

    We will use the following expression.

    K = °C + 273.15 = 23.0 + 273.15 = 296.2 K

    Step 3: Calculate the final temperature of the gas

    Assuming constant pressure and ideal behavior, we can calculate the final temperature of the gas using Charles’ law.

    T₁/V₁ = T₂/V₂

    T₂ = T₁ × V₂/V₁

    T₂ = 296.2 K × 32.0 L/12.0 L = 790 K

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )