Magnesium metal reacts with hydrochloric acid to produce hydrogen gas and a solution of magnesium chloride. Write and balance the chemical e

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Magnesium metal reacts with hydrochloric acid to produce hydrogen gas and a solution of magnesium chloride. Write and balance the chemical equation for this reaction, and determine the volume of the hydrogen gas generated (at 1.00 atm, 25 °C) by reacting 10.0 g Mg with an excess of hydrochloric acid

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  1. Answer:

    Mg + 2 HCl ⇒ MgCl₂ + H₂

    10.1 L

    Explanation:

    Step 1: Write the balanced equation

    Mg + 2 HCl ⇒ MgCl₂ + H₂

    Step 2: Calculate the moles corresponding to 10.0 g of Mg

    The molar mass of Mg is 24.31 g/mol.

    10.0 g × 1 mol/24.31 g = 0.411 mol

    Step 3: Calculate the moles of H₂ produced from 0.411 moles of Mg

    The molar ratio of Mg to H₂ is 1:1. The moles of H₂ produced are 1/1 × 0.411 mol = 0.411 mol

    Step 4: Calculate the volume occupied by 0.411 moles of H₂

    0.411 moles of H₂ are at 1.00 atm and 25 °C (298 K). We can calculate the volume occupied using the ideal gas equation.

    P × V = n × R × T

    V = n × R × T / P

    V = 0.411 mol × (0.0821 atm.L/mol.K) × 298 K / 1.00 atm = 10.1 L

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