???????????????????????????????????????? Lm ơn đó help me. Hứa vote 5*, CTLHN October 25, 2020 by Verity ???????????????????????????????????????? Lm ơn đó help me. Hứa vote 5*, CTLHN
Đáp án: $a) 25a^2 +10a+1$ $ = (5a+1)^2$ $= (5a+1)(5a+1)$ $b) 10ab + 0,25a^2 +100b^2$ $ = 0,25a^2 + 2. 0,5a .10b +100b^2$ $= (0,5a +10b)^2$ $ = (0,5a+10b)(0,5a+10b)$ $c) 9x^2-24x+16y^2$ $ = (3x -4y)^2$ $= (3x-4y)(3x-4y)$ $d) 9x^2-xy+\dfrac{1}{36}y^2$ $ = (3x – \dfrac{1}{6}y)^2$ $ = (3x-\dfrac{1}{6}y)(3x-\dfrac{1}{6}y)$ Reply
a) `25a^2 + 10a + 1` `=(5a)^2 + 2.5a + 1^2` `=(5a+1)^2` b) `10ab + 0,25a^2 +100b^2` `=(0,5a)^2 + 2.0,5.10ab + (10b)^2` `=(0,5a+10b)^2` c) `9x^2 – 24xy + 16y^2` `=(3x)^2 – 2.3x.4y + (4y)^2` `=(3x-4y)^2` d) `9x^2 – xy + 1/36 y^2` `=(3x)^2 – 2.3x. 1/6. y + (1/6y)^2` `=(3x-1/6y)^2` End. Reply
Đáp án:
$a) 25a^2 +10a+1$
$ = (5a+1)^2$
$= (5a+1)(5a+1)$
$b) 10ab + 0,25a^2 +100b^2$
$ = 0,25a^2 + 2. 0,5a .10b +100b^2$
$= (0,5a +10b)^2$
$ = (0,5a+10b)(0,5a+10b)$
$c) 9x^2-24x+16y^2$
$ = (3x -4y)^2$
$= (3x-4y)(3x-4y)$
$d) 9x^2-xy+\dfrac{1}{36}y^2$
$ = (3x – \dfrac{1}{6}y)^2$
$ = (3x-\dfrac{1}{6}y)(3x-\dfrac{1}{6}y)$
a) `25a^2 + 10a + 1`
`=(5a)^2 + 2.5a + 1^2`
`=(5a+1)^2`
b) `10ab + 0,25a^2 +100b^2`
`=(0,5a)^2 + 2.0,5.10ab + (10b)^2`
`=(0,5a+10b)^2`
c) `9x^2 – 24xy + 16y^2`
`=(3x)^2 – 2.3x.4y + (4y)^2`
`=(3x-4y)^2`
d) `9x^2 – xy + 1/36 y^2`
`=(3x)^2 – 2.3x. 1/6. y + (1/6y)^2`
`=(3x-1/6y)^2`
End.