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Asked: Tháng Mười 24, 20202020-10-24T14:28:55+00:00 2020-10-24T14:28:55+00:00In: Môn Toán

lm chs mik bài 2.3 nhé ok con dê

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lm chs mik bài 2.3 nhé ok con dê
lm-chs-mik-bai-2-3-nhe-ok-con-de

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    1. Acacia

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      Acacia
      2020-10-24T14:30:47+00:00Added an answer on Tháng Mười 24, 2020 at 2:30 chiều

      Đáp án:

       a)`max A=9` khi `-4<=x<=5`

      b) `max B=16` khi `-3<=x<=5`

      Giải thích các bước giải:

       bài 2.3:

      `a) A=-|x-5|+x-4=x+4-|x-5|<=|x+4-x+5|=9`

      dấu = xảy ra khi `(x+4)(x-5)>=0⇔-4<=x<=5`

      vậy `max A=9` khi `-4<=x<=5`

      `b) B=-2|x-5|+2x+6`

      `B/2=x+3-|x-5|<=|x+3-x+5|=8`

      `B<=16`

      dấu = có khi `(x+3)(x-5)>=0⇔-3<=x<=5`

      vậy `max B=16` khi `-3<=x<=5`

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    2. Philomena

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      Philomena
      2020-10-24T14:29:57+00:00Added an answer on Tháng Mười 24, 2020 at 2:29 chiều

      `a) A=-|x-5|+x-4`

      `=x+4-|x-5|` $\leq$ `|x+4-x+5|=9`

      Dấu ‘=’ xảy ra khi `(x+4)(x-5`)$\geq$ `0`

      `⇔-4` $\leq$ `x` $\leq$ `5`

      Vậy `Max_A=9` ⇔ `-4<=x<=5`

      `b) B=-2|x-5|+2x+6`

      `B/2=x+3-|x-5|` $\leq$ `|x+3-x+5|=8`

      `B`$\leq$ `16`

      Dấu ‘=’ xảy ra ⇔  `(x+3)(x-5)`$\geq$ `0`

      `⇔-3` $\leq$  `x` $\leq$5`

      Vậy `Max_B=16` ⇔ `-3`$\leq$ `x` $\leq$ `5`

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