Liquid ethyl mercaptan, C2H6S, has a density of 0.84 g/mL. Assuming that the combustion of this compound produces only CO2 , H2O, and SO2 ,

Question

Liquid ethyl mercaptan, C2H6S, has a density of 0.84 g/mL. Assuming that the combustion of this compound produces only CO2 , H2O, and SO2 , what masses of each of these three products would be produced in the combustion of 3.15 mL of ethyl mercaptan

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Vodka 6 months 2021-07-13T19:54:13+00:00 1 Answers 36 views 0

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    2021-07-13T19:55:33+00:00

    Answer:

    Mass CO2 = 3.75 grams

    Mass H2O = 2.30 grams

    Mass SO2 = 2.73 grams

    Explanation:

    Step 1: Data given

    Density of Liquid ethyl mercaptan, C2H6S = 0.84 g/mL

    Volume of ethyl mercaptan = 3.15 mL

    Step 2: The reaction

    2C2H6S + 9O2 → 4CO2 + 6H2O + 2SO2

    Step 3: Calculate mass of ethyl mercaptan

    Mass = Volume * density

    Mass ethyl mercaptan = 3.15 mL * 0.84 g/mL

    Mass ethyl mercaptan = 2.646 grams

    Step 4: Calculate moles ethyl mercaptan

    Moles = mass / molar mass

    Moles ethyl mercaptan = 2.646 grams / 62.13 g/mol

    Moles ethyl mercaptan = 0.04259 moles

    Step 5: Calculate moles of other products

    For 2 moles ethyl mercaptan we need 9 moles O2 to produce 4 moles CO2, 6 moles H2O and 2 moles SO2

    For 0.04259 moles we need 0.1917 moles O2 to produce:

    2*0.04259 = 0.08518 moles CO2

    3*0.04259 = 0.1278 moles H2O

    1*0.04259 = 0.04259 moles SO2

    Step 6: Calculate mass produced

    Mass = moles * molar mass

    Mass CO2 = 0.08518 moles * 44.01 g/mol

    Mass CO2 = 3.75 grams

    Mass H2O = 0.1278 moles * 18.02 g/mol

    Mass H2O = 2.30 grams

    Mass SO2 = 0.04259 moles * 64.07 g/mol

    Mass SO2 = 2.73 grams

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