Limestone has a density of 2.72 g/cm3. What is the mass of 8.92 cm3 of limestone?

Question

Limestone has a density of 2.72 g/cm3. What is the mass of 8.92 cm3 of limestone?

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Ngọc Khuê 6 months 2021-08-24T01:36:33+00:00 2 Answers 0 views 0

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    0
    2021-08-24T01:37:50+00:00

    it should be 24.2624 because if there’s 2.72g in every cm3 and there are 8.92 cm3, then you simply multiply the two numbers
    hope this helped 🙂

    0
    2021-08-24T01:37:55+00:00

    Answer:

    \boxed {\boxed {\sf 24.2624 \ g}}}

    Explanation:

    Density measures mass per volume. The volume is

    \rho=\frac{m}{v}

    The density of limestone is 2.72 grams per cubic centimeter. We have a piece of limestone with a volume of 8.92 cubic centimeters.

    • ρ= 2.72 g/cm³
    • v= 8.92 cm₃

    Substitute the values into the formula.

    2.72 \ g/cm^3=\frac{m}{8.92 \ cm^3}

    Now we solve for m, the mass, by isolating the variable.

    m is being divided by 8.92 cubic centimeters. The inverse of division is multiplication, so we multiply both sides by 8.92 cubic centimeters.

    8.92 \ cm^3 * 2.72 \ g/cm^3=\frac{m}{8.92 \ cm^3}* 8.92 \ cm^2

    8.92 \ cm^3 * 2.72 \ g/cm^3=m

    The units of cubic centimeters cancel out.

    24.2624 \ g =m

    The mass of this piece of limestone is 24.2624 grams.

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