Light of wavelength 580 nm is incident on a slit of width 0.30 mm. An observing screen is placed 2.0 m past the slit. Find the distance on t

Question

Light of wavelength 580 nm is incident on a slit of width 0.30 mm. An observing screen is placed 2.0 m past the slit. Find the distance on the screen of the first order dark fringe from the center of the pattern.

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Thu Cúc 4 years 2021-08-06T01:30:54+00:00 1 Answers 21 views 0

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  1. minhkhue
    0
    2021-08-06T01:32:42+00:00
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    Answer:

    Y = 3.87 x 10⁻³ m = 3.87 mm

    Explanation:

    This problem can be solved by using Young’s double-slit experiment formula:

    Y = \frac{\lambda L}{d}

    where,

    Y = fringe spacing = ?

    L = slit to screen distance = 2 m

    λ = wavelength of light = 580 nm = 5.8 x 10⁻⁷ m

    d = slit width = 0.3 mm = 3 x 10⁻⁴ m

    Therefore,

    Y = \frac{(5.8\ x\ 10^{-7}\ m)(2\ m)}{3\ x\ 10^{-4}\ m}

    Y = 3.87 x 10⁻³ m = 3.87 mm

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