Light is incident along the normal on face AB of a glass prismwith refractive index 1.52. A. Find the largest value the angle α can ha

Question

Light is incident along the normal on face AB of a glass prismwith refractive index 1.52.
A. Find the largest value the angle α can have withoutany light refracted out of the prism at face AC if the prism isimmersed in air.
B. Find the largest value the angle α can have withoutany light refracted out of the prism at face AC if the prism isimmersed in water.
air refactive index = 1.00029
water refractive index = 1.33

in progress 0
Helga 7 months 2021-07-25T20:59:24+00:00 1 Answers 2 views 0

Answers ( )

    0
    2021-07-25T21:00:57+00:00

    Answer:

    48.9°, 29°

    Explanation:

    We kno that snell’s law States that

    ( sin i / sin r ) = ( n 2 / n 1 )

    And here

    i = 90 – α

    r = 90

    n 2 = n a = 1.00029

    n 1 = n = 1.52

    So

    ( sin ( 90 – α ) / sin 90 ) = (1.00029 / 1.52 )

    = 0.658

    sin ( 90 – α ) = 0.658

    90 – α = sin -1 ( 0.658 )

    = 41.15

    α = 90 – 41.15

    = 48.9°

    ( b ) to find angle when prism immerssed in water

    Using snell’s law again

    ( sin i / sin r ) = ( n 2 / n 1 )

    here i = 90 – α

    r = 90

    n 2 = n w = 1.33

    n 1 = n = 1.52

    So

    ( sin ( 90 – α ) / sin 90 ) = (1.33 / 1.52 )

    = 0.875

    sin ( 90 – α ) = 0.875

    90 – α = sin -1 ( 0.875 )

    = 61

    α = 90 – 61

    = 29°

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )