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Jezebel
Jezebel

Jezebel

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Asked: 2020-11-22T22:39:18+00:00 In:

Làm hộ câu F thanksssssss

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Làm hộ câu F thanksssssss
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    2 Answers

    1. Nick

      Nick

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      Đáp án:

       

      Giải thích các bước giải:

      `f,sqrt{4x^2-9}=2sqrt{2x+3}`

      `ĐK:x>=3/2`

      hoặc `x=-3/2`

      `<=>sqrt{(2x-3)(2x+3)}-2sqrt{2x+3}=0`

      `<=>sqrt{2x+3}(sqrt{2x-3}-2)=0`

      `=>`\(\left[ \begin{array}{l}\sqrt{2x+3}=0\\\sqrt{2x-3}-2=0\end{array} \right.\) 
      `=>`\(\left[ \begin{array}{l}x=-\frac{3}{2}\\\sqrt{2x-3}=2\end{array} \right.\) 
      `=>`\(\left[ \begin{array}{l}x=-\frac{3}{2}\\2x-3=4\end{array} \right.\) 
      `=>`\(\left[ \begin{array}{l}x=-\frac{3}{2}(TM)\\x=\frac{7}{2}(TM)\end{array} \right.\) 

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    2. Orla Orla

      Orla Orla

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      Đáp án:

       

      Giải thích các bước giải:

      $\sqrt{4x^2-9}-2\sqrt{2x+3}=0$     $\left (x \geq -\dfrac{3}{2} \right )$

      $⇔\sqrt{(2x-3)(2x+3)}-2\sqrt{2x+3}=0$

      $⇔\sqrt{2x+3}.(\sqrt{2x-3}-2)=0$

      $⇔\left[ \begin{array}{1}\sqrt{2x+3}\\\sqrt{2x-3}=2\end{array} \right.$

      $⇔\left[ \begin{array}{1}x=-\dfrac{3}{2}\\x=\dfrac{7}{2}\end{array} \right.$

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