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Phúc Điền 9 months 2021-04-23T13:23:38+00:00 2 Answers 3 views 0

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  1. haidang
    0
    2021-04-23T13:25:29+00:00
    Reply

    a) 3 1/2 – 1/2x = 2/3

    ⇔7/2 – 1/2x = 2/3

    ⇔1/2x = 7/2 – 2/3

    ⇔1/2x = 21/6 – 2/6

    ⇔1/2x = 19/6

    ⇔x = 19/6 : 1/2

    ⇔x = 19/6 x 2

    ⇔x = 19/3

    b) 1/3 + 2/3 : x = -7

    ⇔2/3 : x = -7 – 1/3

    ⇔2/3 : x = -21/3 – 1/3

    ⇔2/3 : x = -22/3

    ⇔x = 2/3 : -22/3

    ⇔x = 2/3 x 3/-22

    ⇔x = -1/11

    d) (2x – 3)(6 – 2x) = 0

    ⇔[2x-3 = 0

    [6-2x=0

    ⇔[2x=0+3

    [2x=2-0

    ⇔[2x=3

    [2x=6

    ⇔[x=3:2

    [x=6:2

    ⇔[x=3/2

    [x=3

  2. binhan
    0
    2021-04-23T13:25:30+00:00
    Reply

    *Lời giải :

    `a) 3 1/2 – 1/2x = 2/3`

    `-> 7/2 – 1/2x = 2/3`

    `-> 1/2x = 7/2 – 2/3`

    `-> 1/2x = 17/6`

    `-> x = 17/6 : 1/2`

    `-> x = 17/3`

    Vậy `x = 17/3`

    `b) 1/3 + 2/3 😡 = -7`

    `-> 2/3 : x = -7 – 1/3`

    `-> 2/3 : x = (-22)/3`

    `-> x = 2/3 : (-22)/3`

    `-> x = (-1)/11`

    Vậy `x = (-1)/11`

    `c) 1/3x + 2/5 (x – 1) = 0`

    `-> 1/3x + 2/5x – 2/5 = 0`

    `-> (1/3 + 2/5) . x = 0 + 2/5`

    `-> 11/15x = 2/5`

    `-> x = 2/5 : 11/15`

    `-> x = 6/11`

    Vậy `x = 6/11`

    `d) (2x – 3) (6 – 2x) = 0`

    `->` \(\left[ \begin{array}{l}2x-3=0\\6-2x=0\end{array} \right.\) 

    `->` \(\left[ \begin{array}{l}2x=3\\2x=6\end{array} \right.\) 

    `->` \(\left[ \begin{array}{l}x=\dfrac{3}{2}\\x=3\end{array} \right.\) 

    Vậy `x=  3/2` hoặc `x = 3`

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )