Jupiters distance from the Sun is 7.78* 10^11 meters and it takes 3.74*10^8 seconds to complete one revolution of the sun in its rouglhy cir

Question

Jupiters distance from the Sun is 7.78* 10^11 meters and it takes 3.74*10^8 seconds to complete one revolution of the sun in its rouglhy circular orbit. What Is Jupiter’s Angular Speed In Radians/second And Arc-seconds Per Seconds?

in progress 0
5 months 2021-08-27T04:17:01+00:00 1 Answers 7 views 0

Answers ( )

    0
    2021-08-27T04:18:49+00:00

    Answer:

    Jupiter’s angular speed is 1.68*10^-8rad/s or 9.63*10^-6asec/s.

    Explanation:

    Jupiter completes one revolution of the sun in 3.74*10^8 seconds, this means that it travels around a complete circle, of 2π radians, in that time. So, we can express the Jupiter’s angular speed as:

    \omega=\frac{2\pi}{3.74*10^8s} =1.68*10^{-8}rad/s

    In words, Jupiter’s angular speed is 1.68*10^-8 rad/s.

    Now, to express it in arc-seconds per second, or asec/s, we have to multiply it by the factor \frac{3600asec}{2\pi rad}, and we get:

    1.68*10^{-8}rad/s=9.63*10^{-6}asec/s

    Finally, the angular speed is equal to 9.63*10^-6asec/s.

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )