Jet fighter planes are launched from aircraft carriers with the aid of their own engines and a catapult. If in the process of being launched

Question

Jet fighter planes are launched from aircraft carriers with the aid of their own engines and a catapult. If in the process of being launched from rest, the thrust of a jet’s engines is 2.30 105 N and after moving through a distance of 90 m the plane lifts off with a kinetic energy of 3.60 107 J, what is the work done (in J) on the jet by the catapult?

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Thiên Ân 3 months 2021-07-24T14:28:52+00:00 1 Answers 0 views 0

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    2021-07-24T14:30:34+00:00

    Answer:

    The work done on the jet by the catapult is 1.53 x  10⁷ J

    Explanation:

    Given;

    force of thrust engines, F =  2.3 x 10⁵ N

    distance moved by the thrust engines, d =  90 m

    kinetic energy of the plane, K.E = 3.60 x 10⁷ J

    Based on work-energy theorem;

    the net work done on the plane by catapult and the thrust engine is given as;

    W_n = K.E_f = 3.6 *10^7 \ J

    work done by the thrust engine on the jet;

    W_T_._e_n = fd\\\\W_T_._e_n = 2.3*10^5 * 90\\\\W_T_._e_n = 2.07*10^7 \ J

    Work done on the jet by the catapult;

    W_c_p= W_n - W_T_._e_g\\\\W_c_p= (3.6*10^7 - 2.07*10^7) J\\\\W_c_p= 1.53*10^7 \ J

    Therefore, the work done on the jet by the catapult is 1.53 x  10⁷ J

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