Jed Sites The perimeter of an isosceles triangle is 7x + 5y – 8 units, and the length of the base of the triangle is x – y – 2 u

Question

Jed Sites
The perimeter of an isosceles triangle is 7x + 5y – 8 units, and the length of the base of the
triangle is x – y – 2 units. What is the length, in units, of each of the congruent sides of the
triangle?
3x + 2y – 5
3x + 3y – 3
4x + 2y – 5
6x + 4y – 10

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Huyền Thanh 5 years 2021-07-28T04:13:39+00:00 1 Answers 16 views 0

Answers ( )

    0
    2021-07-28T04:15:36+00:00

    Answer:

    Option B: 3x + 3y – 3

    Step-by-step explanation:

    In an isosceles triangle, the two congruent sides are equal.

    We are told the base is; x – y – 2 units

    Now let each of the congruent sides be represented as A.

    Thus the perimeter equation will be;

    P = 2A + x – y – 2

    Now, we are told that the perimeter is; 7x + 5y – 8 units

    Thus;

    7x + 5y – 8 = 2A + x – y – 2

    Rearranging gives;

    7x – x + 5y + y – 8 + 2 = 2A

    2A = 6x + 6y – 6

    Divide through by 2 to give;

    A = 3x + 3y – 3 units

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