James needs 70 liters of 50% antifreeze. He has 30% antifreeze and 80% antifreeze avail- able. How many liters of the 30% antifreeze and how

Question

James needs 70 liters of 50% antifreeze. He has 30% antifreeze and 80% antifreeze avail- able. How many liters of the 30% antifreeze and how many liters of the 80% antifreeze should he mix to make the 50% antifreeze?

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Thiên Di 2 months 2021-07-24T15:14:55+00:00 1 Answers 3 views 0

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    2021-07-24T15:15:56+00:00

    Answer:

    (42,28)

    Step-by-step explanation:

    set up the problem by converting percentages to decimal

    x+y=70

    .30x+.80y=50(x+y)

    solve for x, so minus y in order to get it x alone. equation should look like this: x=70-y

    30(70-y)+80y=50(70-y+y)

    solve the equation for y

    y=28

    plug the value of y into the equation x=70-y

    x=70-28

    solve for x

    x=42

    check the solution of (42,28)

    42+28=70

    30*42+80*28=50(42+28)

    simplify the equations

    70=70

    3500=3500

    the ordered pair is a solution

    so James needs 42 liters of 30% antifreeze and 28 liters of 80% antifreeze.

    (42,28)

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