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Jack had four bags of M&M’s and eight Reese’s cups. He randomly chose a piece of candy, ate it, then chose another. What is the probabil
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Jack had four bags of M&M’s and eight Reese’s cups. He randomly chose a piece of candy, ate it, then chose another. What is the probability that both pieces of candy were Reese’s cups. Show work.
please help me!!!
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Mathematics
1 year
2021-09-03T22:11:46+00:00
2021-09-03T22:11:46+00:00 1 Answers
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Answers ( )
Total = 12
P(M&Ms) = 4/12
P(Reese’s) = 8/12
8/12 (before he ate it)
7/11 (after he ate it)
Multiply the fractions
56/132 reduce to 14/33 (or you can leave it)
about 42.4%