Jack had four bags of M&M’s and eight Reese’s cups. He randomly chose a piece of candy, ate it, then chose another. What is the probabil

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Jack had four bags of M&M’s and eight Reese’s cups. He randomly chose a piece of candy, ate it, then chose another. What is the probability that both pieces of candy were Reese’s cups. Show work.

please help me!!!​

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Linh Đan 1 year 2021-09-03T22:11:46+00:00 1 Answers 5 views 0

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    2021-09-03T22:12:48+00:00

    Total = 12
    P(M&Ms) = 4/12
    P(Reese’s) = 8/12

    8/12 (before he ate it)
    7/11 (after he ate it)

    Multiply the fractions
    56/132 reduce to 14/33 (or you can leave it)
    about 42.4%

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