Jack and Jill are maneuvering a 3100 kg boat near a dock. Initially the boat’s position is < 2, 0, 3 > m and its speed is 1.6 m/s. As

Question

Jack and Jill are maneuvering a 3100 kg boat near a dock. Initially the boat’s position is < 2, 0, 3 > m and its speed is 1.6 m/s. As the boat moves to position < 6, 0, 1 > m, Jack exerts a force of < -440, 0, 220 > N, and Jill exerts a force of < 170, 0, 340 > N.

How much work does Jack do?
How much work does Jill do?

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Ben Gia 5 months 2021-08-31T05:58:54+00:00 1 Answers 3 views 0

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    2021-08-31T06:00:19+00:00

    Answer:

    (a) work done by Jack is -2200J

    (b) work done by Jill is 0

    Explanation:

    Given;

    Initially boat’s position =  < 2, 0, 3 > m

    Final boat’s position = < 6, 0, 1 > m

    change in position = < 4, 0, -2 >

    Force exerted by Jack =  < -440, 0, 220 > N

    Force exerted by Jill = < 170, 0, 340 > N

    Part (a) How much work does Jack do?

    work done = force x distance

    Jack’s work = < -440, 0, 220 > N x < 4, 0, -2 > m

                        = [(-440*4) + (0*0) + (220*-2)]

                        = -1760 J – 440 J

                        = -2200J

    Part (b) How much work does Jill do?

    Jill’s work = < 170, 0, 340 > N x < 4, 0, -2> m

                     = [(170*4) + (0*0) + (340*-2)]

                      = 680 J – 680 J

                       = 0

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )