It took 20.0 mL of NaOH to neutralize 25 mL of 0.50 M HCl. What is the molarity of the base?

Question

It took 20.0 mL of NaOH to neutralize 25 mL of 0.50 M HCl. What is the molarity of the base?

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MichaelMet 4 years 2021-08-01T13:33:38+00:00 1 Answers 4 views 0

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  1. thaiduong
    0
    2021-08-01T13:34:42+00:00
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    Answer:

    5/8 M

    Explanation:

    NaOH + HCl ====> NaCl + H2O

    in 25 mL of 0.5M acid, we have 1/80 Mol of HCl

    it mean we must have 1/80 Mol of NaOH.

    20 mL = 1/50 L

    (1/80)Mol / (1/50)L = 5/8 M

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