It takes a minimum distance of 98.26 m to stop a car moving at 17.0 m/s by applying the brakes (without locking the wheels). Assume that the

Question

It takes a minimum distance of 98.26 m to stop a car moving at 17.0 m/s by applying the brakes (without locking the wheels). Assume that the same frictional forces apply and find the minimum stopping distance when the car is moving at 25.0 m/s.

in progress 0
Helga 2 months 2021-07-19T07:55:22+00:00 1 Answers 1 views 0

Answers ( )

    0
    2021-07-19T07:57:17+00:00

    Answer:

    x_f = 212.5m

    Explanation:

    t = (x_f-x_0)/(.5*(v_f-v_0))

    t = (98.26m-0m)/(.5(0m/s-17m/s))

    t = 11.56s

    a = (v_f-v_0)/t

    a = (0m/s-17m/s)/11.56s

    a = -1.47m/s²

    t = (v_f-v_0)/a

    t = (0m/s-25m/s)/-1.47m/s²

    t = 17s

    x_f = x_0+(.5*(v_f-v_0))*t

    x_f = 0m+(.5*(0m/s-25m/s))*17s

    x_f = 212.5m

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )