is a(t) = 1200(1 + .03)t a decay function?

Question

is a(t) = 1200(1 + .03)t a decay function?

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Orla Orla 2 months 2021-07-21T12:35:37+00:00 1 Answers 3 views 0

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    2021-07-21T12:36:41+00:00

    Answer:

    Step-by-step explanation:

    No, it is an exponential growth function because 1.03>1. An exponential decay function would have a rate less than 1.

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