In triangle ABC, what is the measure of b if a = 51, c = 38, and B = 41°? Round the answer to the nearest hundredth.

Question

In triangle ABC, what is the measure of b if a = 51, c = 38, and B = 41°?
Round the answer to the nearest hundredth.

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Thành Đạt 6 months 2021-07-27T04:06:36+00:00 1 Answers 11 views 0

Answers ( )

    0
    2021-07-27T04:07:46+00:00

    Answer:

    33.46

    Step-by-step explanation:

    Using the cosine rule;

    b² = a²+c²-2accosB

    b² = 51²+38²-2(51)(38)cos41

    b² = 2601+1444-2(51)(38)cos41

    b² = 4045-2,925.25

    b² = 1,119.74

    b = √1,119.74

    b = 33.46

    Hence the value of b to nearest hundredth is 33.46

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