In the sketch, a bar is moving to the right at constant speed of 30.0 m/s in a uniform magnetic field of 8.0 T directed into the page. The r

Question

In the sketch, a bar is moving to the right at constant speed of 30.0 m/s in a uniform magnetic field of 8.0 T directed into the page. The resistance R is 6.0 . The separation L between the rails is 3.0 m. The bar slides with no friction while making continuous electrical contact with the rails. Find the current flowing in the resistor and the direction of the current.

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bonexptip 4 years 2021-08-02T08:10:20+00:00 2 Answers 11 views 0

Answers ( )

  1. Vodka
    0
    2021-08-02T08:11:56+00:00
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    Answer:

    Explanation:

    P.d between the ends of the rods is given by

    E =vBL = 8*5*3= 120v

    To find current V= IR

    120v/ 6ohms= 20A

    Thus according to lenz law the direction of current is counterclockwise

  2. Xavia
    0
    2021-08-02T08:12:00+00:00
    Reply

    Complete Question

    The diagram for this question is shown on the first uploaded image

     

    Answer:

    The current is I= 120 A

    the direction is counter clockwise

    Explanation:

    From the question we are told that

           The speed of the bar is  v = 30.0m/s

            The magnetic field is B = 8.0 T

            The resistace is R = 6.0\ \Omega

           The seperation is L = 3.0m

    The induced emf due to the change in magnetic flux as a result of the bar

    sliding is mathematically represented as

        \epsilon = -B lv

    Substituting values

        \epsilon =- 8.0 * 30 * 3

         = - 720V

     According to ohm law

            I = \frac{|\epsilon|}{R}

    Substituting values

        I = \frac{|-720|}{6}

          I= 120 A

         According to Lenz’s law the emf should be opposing the magnetic force  which produced it so since the magnetic force is  moving in the clockwise direction the current due to the emf would be moving in a counter clockwise direction

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