In the lab, you submerge 100 g of 40°C nails in 200 g of 20°C water. (The specific heat of iron is 0.12 cal/g # °C.) Equate the heat gained

Question

In the lab, you submerge 100 g of 40°C nails in 200 g of 20°C water. (The specific heat of iron is 0.12 cal/g # °C.) Equate the heat gained by the water to the heat lost by the nails, and show that the final temperature of the water is about 21°C.

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Thu Nguyệt 2 months 2021-08-03T16:56:12+00:00 1 Answers 2 views 0

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    2021-08-03T16:58:08+00:00

    Answer:

    Final temperature of the mixture becomes

    T = 21.13^oC

    Explanation:

    Here we know that heat given by the nail is equal to the heat absorbed by water

    So here we know that heat to change the temperature is given as

    Q = ms\Delta T

    so by equating the heat we have

    m_{iron}s_{iron}\Delta T = m_{water}s_{water}\Delta T

    now we have

    100 (0.12) (40 - T) = 200 (1) (T - 20)

    4.8 - 0.12 T = 2T - 40

    44.8 = 2.12 T

    T = 21.13^oC

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