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In the Bohr model of the hydrogen atom (see Section 38.5), in the lowest energy state the electron orbits the proton at a speed of 2.2 * 106
Question
In the Bohr model of the hydrogen atom (see Section 38.5), in the lowest energy state the electron orbits the proton at a speed of 2.2 * 106 m/s in a circular orbit of radius 5.3 * 10-11 m. (a) What is the orbital period of the electron?
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2021-09-05T07:43:58+00:00
2021-09-05T07:43:58+00:00 1 Answers
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Answers ( )
Answer:
Orbital period of electron is 1.5×10⁻¹⁶s
Explanation:
Given data
Proton speed v=2.2×10⁶m/s
Radius r=5.3×10⁻¹¹m
To find
Orbital period of electron T
Solution
We need to find the orbital period of electron the period is given by:
[tex]T=\frac{2\pi r}{v} \\[/tex]
Substitute the given values
[tex]T=\frac{2\pi (5.3*10^{-11}m)}{2.2*10^{6}m/s }\\ T=1.5*10^{-16}s[/tex]
Orbital period of electron is 1.5×10⁻¹⁶s