In the Bohr model of the hydrogen atom (see Section 38.5), in the lowest energy state the electron orbits the proton at a speed of 2.2 * 106

Question

In the Bohr model of the hydrogen atom (see Section 38.5), in the lowest energy state the electron orbits the proton at a speed of 2.2 * 106 m/s in a circular orbit of radius 5.3 * 10-11 m. (a) What is the orbital period of the electron?

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Yến Oanh 1 week 2021-09-05T07:43:58+00:00 1 Answers 0 views 0

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    2021-09-05T07:45:15+00:00
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    Answer:

    Orbital period of electron is 1.5×10⁻¹⁶s

    Explanation:

    Given data

    Proton speed v=2.2×10⁶m/s

    Radius r=5.3×10⁻¹¹m

    To find

    Orbital period of electron T

    Solution

    We need to find the orbital period of electron the period is given by:

    T=\frac{2\pi r}{v} \\

    Substitute the given values

    T=\frac{2\pi (5.3*10^{-11}m)}{2.2*10^{6}m/s }\\ T=1.5*10^{-16}s

    Orbital period of electron is 1.5×10⁻¹⁶s

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