In the 2016 Olympics in Rio, after the 50 m freestyle competition, a problem with the pool was found. In lane 1 there was a gentle 1.2 cm/s

Question

In the 2016 Olympics in Rio, after the 50 m freestyle competition, a problem with the pool was found. In lane 1 there was a gentle 1.2 cm/s current flowing in the direction that the swimmers were going, while in lane 8 there was a current of the same speed but directed opposite to the swimmers’ direction. Suppose a swimmer could swim the 50.0 m in 25.0 s in the absence of any current.

Part A: How would the time it took the swimmer to swim 50.0 m change in lane 1?

Part B: How would the time it took the swimmer to swim 50.0 m change in lane 8?

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Bơ 4 years 2021-07-15T07:44:18+00:00 1 Answers 4 views 0

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  1. hongcuc2
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    2021-07-15T07:46:11+00:00
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    Answer:

    Explanation:

    A )

    speed of swimming in still water is given by the expression

    distance / time

    = 50 / 25

    = 2 m /s

    In lane 1 , 1.2 cm/s current is flowing in the direction that the swimmers are going so swimmers will cover distance at the rate of  2 + 1.2 = 3.2 m /s.

    time to cover distance of 50 m in lane 1

    = distance / speed

    = 50 / 3.2 = 15.625 s

    In lane 8 , 1.2 cm/s current is flowing against  the direction that the swimmers are going so swimmers will cover distance at the rate of  2 – 1.2 = .8 m /s.

    time to cover distance of 50 m in lane 1

    = distance / speed

    = 50 / .8 = 62.5 s

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