In preparing to shoot an arrow, an archer pulls a bow string back 0.424 m by exerting a force that increases uniformly from 0 to 223 N. What

Question

In preparing to shoot an arrow, an archer pulls a bow string back 0.424 m by exerting a force that increases uniformly from 0 to 223 N. What is the equivalent spring constant of the bow?

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RobertKer 4 years 2021-09-02T06:09:14+00:00 1 Answers 8 views 0

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  1. thanhcong
    0
    2021-09-02T06:10:39+00:00
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    Answer:

    525.94N/m

    Explanation:

    According to Hooke’s law, the extension or compression of an elastic material is proportional to an applied force provided that the elastic limit of the material is not exceeded.

    F=ke..................(1)

    where  F is the applied force or load, k is the elastic constant or stiffness of the material and e is the extension.

    In this problem, the bow string is assumed to behave like an elastic material that is stretched not beyond the elastic limit.

    Given;

    F = 223N;

    e = 0.424m

    k = ?

    We make substitutions into equation (1) and then solve for k.

    223=k*0.424\\k=\frac{223N}{0.424m}\\k = 525.94N/m

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