In order to determine the lattice formation energy for KCl, the following data are provided: Ionization energy of K(g) = 425 kJ

Question

In order to determine the lattice formation energy for KCl, the following data are provided:

Ionization energy of K(g) = 425 kJ/mol
Electron affinity of Cl(g) = –349 kJ/mol
Energy to sublime K(s) = 89 kJ/mol
Bond energy of Cl2(g) = 240 kJ/mol
ΔHf for K(s) + ½Cl2(g) → KCl(s) = –438 kJ/mol

Sort the steps of the Born–Haber cycle according to the sign of the energy change associated with each.

K(g) → K^(g)+ e
K^+(g) + Cl^- →KCl(s)
K(s) + K(g)

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Nick 4 years 2021-07-28T01:12:13+00:00 1 Answers 40 views 0

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    -1
    2021-07-28T01:13:24+00:00

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