In ΔIJK, i = 74 inches, j = 23 inches and ∠K=20°. Find the area of ΔIJK, to the nearest square inch.

Question

In ΔIJK, i = 74 inches, j = 23 inches and ∠K=20°. Find the area of ΔIJK, to the nearest square inch.

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RobertKer 2 months 2021-07-18T23:17:11+00:00 1 Answers 4 views 0

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    2021-07-18T23:18:50+00:00

    Answer:

    291in^2

    Step-by-step explanation:

    Using the formula

    Area of the triangle = 1/2absin theta

    A = 1/2ijsin<K

    Given

    i = 74in

    j = 23in

    <K = 20 degrees

    Area = 1/2 * 74*23sin20

    Area = 37*23sin20

    Area = 852sin20

    Area = 291.059in^2

    Hence the area of the triangle to nearest square inch is 291in^2

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