In an oscillating LC circuit, the maximum charge on the capacitor is qm. Determine the charge on the capacitor, q, and the current through t

Question

In an oscillating LC circuit, the maximum charge on the capacitor is qm. Determine the charge on the capacitor, q, and the current through the inductor, I, when energy is shared equally between the electric and magnetic fields. Express your answers in terms of qm, L, and C.

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Nho 6 months 2021-08-14T05:31:54+00:00 1 Answers 8 views 0

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    2021-08-14T05:33:16+00:00

    Answer:

    a. q = qm/√2 b. qm/√(2LC)

    Explanation:

    a. Charge on the capacitor

    Let U₁ = energy in inductor and U₂ = energy in capacitor and U = total energy in circuit.

    So, U₁ + U₂ = U.

    Since the energy is shared equally between the capacitor and inductor, U₁= U₂,so

    2U₂ = U

    and U₂ = U/2

    Now U₂ = q²/2C where q is the charge on the capacitor with capacitance C and

    U = (qm)²/2C where qm is the maximum charge on the capacitor.

    Since U₂ = U/2,

    Substituting the values for U₂ and U, we have

    q²/2C = [(qm)²/2C]/2

    q² = (qm)²/2

    taking square-root of both sides, we have

    q = qm/√2

    b. The current in the inductor

    Since the energy in the capacitor equals the energy in the inductor,

    1/2LI² = 1/2q²/C where L is the inductance of the inductor and I the current through it.

    I² = q²/LC

    taking square-root of both sides, we have

    I = q/√LC

    substituting the value of q from above, we have

    I = qm/√2 ÷ √LC

    I = qm/√(2LC)

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