In an experiment, an object is released from rest from the top of a building. Its speed is measured as it reaches a point that is a distance

Question

In an experiment, an object is released from rest from the top of a building. Its speed is measured as it reaches a point that is a distance d from the point of release. If this distance was doubled, what would the new speed be, assuming air resistance is negligible?

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Maris 3 months 2021-08-23T22:55:34+00:00 1 Answers 0 views 0

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  1. Nem
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    2021-08-23T22:56:36+00:00
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    Answer:

    so the speed will increase by 1.44 times then the initial speed if the distance is increased to double

    Explanation:

    As we know that the air friction or resistance due to air is neglected then we can use the equation of kinematics here

    v_f^2 - v_i^2 = 2 a d

    since we released it from rest so we have

    v_i = 0

    so here we have

    v_f = \sqrt{2gd}

    now if the distance is double then we have

    v_f' = \sqrt{2g(2d)}

    now from above two equations we can say that

    v_f' = \sqrt2 v_f

    so the speed will increase by 1.44 times then the initial speed if the distance is increased to double

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