in a young’s double-slit experiment the center of a bright fringe occurs wherever waves from the slits differ in the distance they travel by

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in a young’s double-slit experiment the center of a bright fringe occurs wherever waves from the slits differ in the distance they travel by a multiple of

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Mộc Miên 5 months 2021-08-02T21:14:50+00:00 1 Answers 92 views 0

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    2021-08-02T21:16:23+00:00

    Answer:

    The path difference will be zero.

    Explanation:

    Given that,

    In a young’s double-slit experiment the center of a bright fringe occurs wherever waves from the slits differ in the distance.

    Suppose, we find the multiple of wavelength

    In young’s double slit experiment,

    We need to calculate the multiple of wavelength

    Using formula of path difference

    \Delta x=d\sin\theta….(I)

    d\sin\theta=m\lambda

    Where, m = fringe number

    \lambda = wavelength

    For center of a bright fringe ,

    m = 0

    Put the value into the formula

    d\sin\theta=0\times\lambda

    d\sin\theta=0

    Put the value in equation (I)

    \Delta x=0

    Hence, The path difference will be zero.

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