In a test of a heat-seeking rocket, a first rocket is launched at 2000 fts and the heat-seeking rocket is launched along the same flight pat

Question

In a test of a heat-seeking rocket, a first rocket is launched at 2000 fts and the heat-seeking rocket is launched along the same flight path 20 s later at a speed of 3000 fts. Find
the timest, and t, of flight of the rockets until the heat-seeking rocket destroys the first rocket
What are the times of the flight?

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Thạch Thảo 4 years 2021-08-07T02:59:59+00:00 1 Answers 33 views 0

Answers ( )

  1. Sapo1
    0
    2021-08-07T03:01:19+00:00
    Reply

    Answer:

    Time of flight of first rocket = 60 seconds

    Time of flight of second rocket = 40 seconds

    Step-by-step explanation:

    Let the time of flight of first rocket be t1.

    Since the second rocket is launched 20 seconds later, then it means that;

    t1 = t2 + 20

    Where t2 is the time of flight of the second rocket.

    When destruction has occurred, it means that both of the rockets would have covered the same distance.

    We know that;

    Distance = speed × time

    Thus;

    2000t1 = 3000t2

    We know that t1 = t2 + 20

    Thus;

    2000(t2 + 20) = 3000t2

    2000t2 + 40000 = 3000t2

    3000t2 – 2000t2 = 40000

    1000t2 = 40000

    t2 = 40000/1000

    t2 = 40 seconds

    Thus;

    t1 = 40 + 20

    t1 = 60 seconds

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