In a set of three lines, a pair of parallel lines is intersected by a transversal. The intersection forms eight special angles. Two of the s

Question

In a set of three lines, a pair of parallel lines is intersected by a transversal. The intersection forms eight special angles. Two of the special angles, A and B, are corresponding angles.

For the set of parallel lines intersected by a transversal, A=4x and B=-5(x-18).

Part A: Write an equation to represent the corresponding relationship betweenA andB.
Part B: Use the equation to find the measures of A and B.

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Dulcie 3 months 2021-09-05T06:45:25+00:00 1 Answers 5 views 0

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    2021-09-05T06:46:51+00:00

    Answer:

    Part A: 4x = -5(x-18)

    Part B: A and B both = 40 degrees

    Step-by-step explanation:

    Ok, corresponding angles are in the same position on the two parallel lines cut by the transversal. And they are equal in measure. So, upper right = upper right.

    So A = B

    4x = -5(x -18)

    4x = -5x + 90

    9x = 90

    x = 10

    Angle A = 4x = 40 degrees, which means angle B is also 40, but let’s show the work:

    Angle B = -5(x – 18) = -50 + 90 = 40

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